3g urea is dissolved in 45g of water. The relative lowering of vapour pressure is:
A) 0.05 B) 0.04 C) 0.02 D) 0.01 Solution Urea = Mass/ mol mass. 3/60. = 0.05 Water= Mass/ mol mass. 45/60. = 2.5 By relative lowering of vapour pressure ∆P/Po. =. X(water) 0.05/0.05+2.5 = 0.0196 = 0.02 is the answer