A) 0.05
B) 0.04
C) 0.02
D) 0.01
Solution
Urea = Mass/ mol mass. 3/60. = 0.05
Water= Mass/ mol mass. 45/60. = 2.5
By relative lowering of vapour pressure
∆P/Po. =. X(water)
0.05/0.05+2.5
= 0.0196
= 0.02 is the answer
Educational NEET Chemistry
A) 0.05
B) 0.04
C) 0.02
D) 0.01
Solution
Urea = Mass/ mol mass. 3/60. = 0.05
Water= Mass/ mol mass. 45/60. = 2.5
By relative lowering of vapour pressure
∆P/Po. =. X(water)
0.05/0.05+2.5
= 0.0196
= 0.02 is the answer