__Option__

A) 120

B) 125

C) 144

D) 81

*Detailed solution*

We know that a+b=6 and ab=4.

Using (a+b)^{2} = a^{2} + b^{2} + 2ab

a^{2 }+ b^{2} = (a+b)^{2} -2ab

a^{2} + b^{2} = 62 -2×4

a^{2} + b^{2} = 28

Using

(a^{3} + b^{3}) = (a+b) (a^{2 }+ b^{2} – ab)

= ( 6 ) ( 28 – 4)

= 144

**ANSWER 44**