Option
A) 120
B) 125
C) 144
D) 81
Detailed solution
We know that a+b=6 and ab=4.
Using (a+b)2 = a2 + b2 + 2ab
a2 + b2 = (a+b)2 -2ab
a2 + b2 = 62 -2×4
a2 + b2 = 28
Using
(a3 + b3) = (a+b) (a2 + b2 – ab)
= ( 6 ) ( 28 – 4)
= 144
ANSWER 44
Educational NEET Chemistry
Option
A) 120
B) 125
C) 144
D) 81
Detailed solution
We know that a+b=6 and ab=4.
Using (a+b)2 = a2 + b2 + 2ab
a2 + b2 = (a+b)2 -2ab
a2 + b2 = 62 -2×4
a2 + b2 = 28
Using
(a3 + b3) = (a+b) (a2 + b2 – ab)
= ( 6 ) ( 28 – 4)
= 144
ANSWER 44