A train starts from a place S at 10.00 am and arrives at another phase T at 2.30 pm on the same day. If the speed of the train is 40m/s then what will be the distance covered by the train?

Options

A) 706
B) 648
C) 726
D) 616

Solution

Train starts from place S, 10 Am
Stops at T at 2.30 Am

Total time taken from 10Am to 2.30 pm is 4.1/2 hrs

Speed of the train is 40 m/s
First should convert m/s to km/r, by multiply with 18/5

40× 18/5 = 144 km/hr

Asked to find distance

Distance = speed × time
= 144 × 4.5
= 648

Answer 648